26x^2-26x+1=0

Solution for 26x^2-26x+1=0 equation:

26x^2-26x+1=0

a = 26; b = -26; c = +1;
Δ = b2-4ac
Δ = -262-4·26·1
Δ = 572
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{572}=\sqrt{4*143}=\sqrt{4}*\sqrt{143}=2\sqrt{143}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{143}}{2*26}=\frac{26-2\sqrt{143}}{52}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{143}}{2*26}=\frac{26+2\sqrt{143}}{52}
$